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Validate numbers

If Possible, Don't Use Regex To Validate Numbers. If at all possible, use your language. There may be functions to help you determine if the value contained by a string is a valid number. That being said, if you're accepting a variety of formats (commas, etc.) you may not have a choice.

Tags: #digits, #numbers, #parsing, #real number, #validate, #validating. Views: 2067. stackoverflow, 7/12/2015
Link 1: http://www.systemtextregularexpressions.com/m13/validate-numbers
Link 2: http://www.systemtextregularexpressions.com/m13 (short)

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RegexOptions

IsMatch=true

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Source code

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//.NET Regex.Match Online Tester: www.systemtextregularexpressions.com

//Namespace
using System.Text.RegularExpressions;

//Regex Pattern
string pattern = @"^([0]|\d{1,2})(?:,\d{1,2})?$";

//Regex example #1
Regex r = new Regex(@"^([0]|\d{1,2})(?:,\d{1,2})?$", RegexOptions.Multiline);
Match m1 = r.Match("input text");
MatchCollection mc1 = r.Matches("input text");

//Regex example #2
Match m2 = Regex.Match("input text", @"^([0]|\d{1,2})(?:,\d{1,2})?$", RegexOptions.Multiline);
MatchCollection mc2 = Regex.Matches("input text", @"^([0]|\d{1,2})(?:,\d{1,2})?$", RegexOptions.Multiline);
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'.NET Regex.Match Online Tester: www.systemtextregularexpressions.com

'Namespace
Imports System.Text.RegularExpressions

'Regex Pattern
Dim pattern As String = "^([0]|\d{1,2})(?:,\d{1,2})?$"

'Regex example #1
Dim r As Regex = New Regex("^([0]|\d{1,2})(?:,\d{1,2})?$", RegexOptions.Multiline)
Dim m1 As Match = r.Match("input text")
Dim mc As MatchCollection = r.Matches("input text")

'Regex example #2
Dim m2 As Match = Regex.Match("input text", "^([0]|\d{1,2})(?:,\d{1,2})?$", RegexOptions.Multiline)
Dim mc2 As MatchCollection = Regex.Matches("input text", "^([0]|\d{1,2})(?:,\d{1,2})?$", RegexOptions.Multiline)

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